If \[P(A\cup B)=0.8\] and \[P(A\cap B)=0.3,\] then \[P(\bar{A})+P(\bar{B})=\] [EAMCET 2003]

If \[P(A\cup B)=0.8\] and \[P(A\cap B)=0.3,\] then \[P(\bar{A})+P(\bar

1.	If \[P(A\cup B)=0.8\] and \[P(A\cap B)=0.3,\] then \[P(\bar{A})+P(\bar{B})=\] [EAMCET 2003]
A.	0.3
B.	0.5
C.	0.7
D.	0.9
Answer» E.

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If \[P(A\cup B)=0.8\] and \[P(A\cap B)=0.3,\] then \[P(\bar{A})+P(\bar{B})=\] [EAMCET 2003]

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