1.

If \[\overrightarrow{A}=\overrightarrow{B}-\overrightarrow{C}\], then, the angle between \[\overrightarrow{A}\] and \[\overrightarrow{B}\] is

A. \[\text{ta}{{\text{n}}^{-1}}\frac{{{B}^{2}}+{{A}^{2}}-{{C}^{2}}}{2AB}\]          
B. \[{{\sin }^{-1}}\frac{{{B}^{2}}+{{A}^{2}}-{{C}^{2}}}{2AB}\]
C. \[{{\cos }^{-1}}\frac{{{A}^{2}}+{{B}^{2}}-{{C}^{2}}}{2AB}\]    
D. \[{{\sec }^{-1}}\frac{{{A}^{2}}+{{B}^{2}}-{{C}^{2}}}{2AB}\]
Answer» D. \[{{\sec }^{-1}}\frac{{{A}^{2}}+{{B}^{2}}-{{C}^{2}}}{2AB}\]


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