If n is a positive integer, then \[{{(1+i)}^{n}}+{{(1-i)}^{n}}\] is equal to [Orissa JEE 2003]

\[{{(\sqrt{2})}^{n+2}}\sin \left( \frac{n\pi }{4} \right)\]

\[{{(\sqrt{2})}^{n-2}}\cos \left( \frac{n\pi }{4} \right)\]

\[{{(\sqrt{2})}^{n-2}}\sin \left( \frac{n\pi }{4} \right)\]

\[{{(\sqrt{2})}^{n+2}}\cos \left( \frac{n\pi }{4} \right)\]

If n is a positive integer, then \[{{(1+i)}^{n}}+{{(1-i)}^{n}}\] is eq

1.	If n is a positive integer, then \[{{(1+i)}^{n}}+{{(1-i)}^{n}}\] is equal to [Orissa JEE 2003]
A.	\[{{(\sqrt{2})}^{n-2}}\cos \left( \frac{n\pi }{4} \right)\]
B.	\[{{(\sqrt{2})}^{n-2}}\sin \left( \frac{n\pi }{4} \right)\]
C.	\[{{(\sqrt{2})}^{n+2}}\cos \left( \frac{n\pi }{4} \right)\]
D.	\[{{(\sqrt{2})}^{n+2}}\sin \left( \frac{n\pi }{4} \right)\]
Answer» D. \[{{(\sqrt{2})}^{n+2}}\sin \left( \frac{n\pi }{4} \right)\]

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If n is a positive integer, then \[{{(1+i)}^{n}}+{{(1-i)}^{n}}\] is equal to [Orissa JEE 2003]

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