If \[n\] geometric means be inserted between \[a\] and \[b\]then the \[{{n}^{th}}\] geometric mean will be

\[a\,{{\left( \frac{b}{a} \right)}^{\frac{1}{n}}}\]

\[a\,{{\left( \frac{b}{a} \right)}^{\frac{n}{n-1}}}\]

\[a\,{{\left( \frac{b}{a} \right)}^{\frac{n-1}{n}}}\]

\[a\,{{\left( \frac{b}{a} \right)}^{\frac{n}{n+1}}}\]

If \[n\] geometric means be inserted between \[a\] and \[b\]then the \

1.	If \[n\] geometric means be inserted between \[a\] and \[b\]then the \[{{n}^{th}}\] geometric mean will be
A.	\[a\,{{\left( \frac{b}{a} \right)}^{\frac{n}{n-1}}}\]
B.	\[a\,{{\left( \frac{b}{a} \right)}^{\frac{n-1}{n}}}\]
C.	\[a\,{{\left( \frac{b}{a} \right)}^{\frac{n}{n+1}}}\]
D.	\[a\,{{\left( \frac{b}{a} \right)}^{\frac{1}{n}}}\]
Answer» D. \[a\,{{\left( \frac{b}{a} \right)}^{\frac{1}{n}}}\]

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If \[n\] geometric means be inserted between \[a\] and \[b\]then the \[{{n}^{th}}\] geometric mean will be

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