MCQOPTIONS
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| 1. |
If \(\mathop \sum \limits_{i = 1}^{20} {\left( {\frac{{{}_\;^{20}{C_{i - 1}}}}{{{}_\;^{20}{C_i} + {}_\;^{20}{C_{i - 1}}}}} \right)^3} = \frac{k}{{21}}\), then ‘k’ is equal to: |
| A. | 400 |
| B. | 50 |
| C. | 200 |
| D. | 100 |
| Answer» E. | |