If \[{{\log }_{x}}a,\ {{a}^{x/2}}\] and \[{{\log }_{b}}x\] are in G.P., then \[x=\]

\[{{\log }_{a}}({{\log }_{e}}b)-{{\log }_{a}}({{\log }_{e}}a)\]

\[-{{\log }_{a}}({{\log }_{a}}b)\]

\[{{\log }_{a}}({{\log }_{e}}a)-{{\log }_{a}}({{\log }_{e}}b)\]

If \[{{\log }_{x}}a,\ {{a}^{x/2}}\] and \[{{\log }_{b}}x\] are in G.P.

1.	If \[{{\log }_{x}}a,\ {{a}^{x/2}}\] and \[{{\log }_{b}}x\] are in G.P., then \[x=\]
A.	\[-\log ({{\log }_{b}}a)\]
B.	\[-{{\log }_{a}}({{\log }_{a}}b)\]
C.	\[{{\log }_{a}}({{\log }_{e}}a)-{{\log }_{a}}({{\log }_{e}}b)\]
D.	\[{{\log }_{a}}({{\log }_{e}}b)-{{\log }_{a}}({{\log }_{e}}a)\]
Answer» D. \[{{\log }_{a}}({{\log }_{e}}b)-{{\log }_{a}}({{\log }_{e}}a)\]

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If \[{{\log }_{x}}a,\ {{a}^{x/2}}\] and \[{{\log }_{b}}x\] are in G.P., then \[x=\]

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