If $$\log 3\log \left( {{3^x} - 2} \right)\,$$and $$\log \left( {{3^x} + 4} \right)$$are in arithmetic progression, then x is equal to

If $$\log 3\log \left( {{3^x} - 2} \right)\,$$and $$\log \left( {{3^x}

1.	If $$\log 3\log \left( {{3^x} - 2} \right)\,$$and $$\log \left( {{3^x} + 4} \right)$$are in arithmetic progression, then x is equal to
A.	$\frac{8}{3}$$
B.	$\log {3^8}$$
C.	$\log {2^3}$$
Answer» D.