If lines \[x=y=z\] and \[x=\frac{y}{2}=\frac{z}{3}\] and third line passing through (1, 1, 1) form a triangle of area \[\sqrt{6}\] units, then the point of intersection of third line with the second line will be

\[\left( \frac{4}{3},\frac{8}{3},\frac{12}{3} \right)\]

If lines \[x=y=z\] and \[x=\frac{y}{2}=\frac{z}{3}\] and third line pa

1.	If lines \[x=y=z\] and \[x=\frac{y}{2}=\frac{z}{3}\] and third line passing through (1, 1, 1) form a triangle of area \[\sqrt{6}\] units, then the point of intersection of third line with the second line will be
A.	\[(1,2,3)\]
B.	\[(2,4,6)\]
C.	\[\left( \frac{4}{3},\frac{8}{3},\frac{12}{3} \right)\]
D.	None of these
Answer» C. \[\left( \frac{4}{3},\frac{8}{3},\frac{12}{3} \right)\]

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If lines \[x=y=z\] and \[x=\frac{y}{2}=\frac{z}{3}\] and third line passing through (1, 1, 1) form a triangle of area \[\sqrt{6}\] units, then the point of intersection of third line with the second line will be

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