If \[\left| {{z}_{1}} \right|=\left| {{z}_{2}} \right|=.......\left| {{z}_{n}} \right|=1,\] then the value of \[\left| {{z}_{1}}+{{z}_{2}}+....{{z}_{n}} \right|-\left| \frac{1}{{{z}_{1}}}+\frac{1}{{{z}_{2}}}+......+\frac{1}{{{z}_{n}}} \right|\] is,

If \[\left| {{z}_{1}} \right|=\left| {{z}_{2}} \right|=.......\left| {

1.	If \[\left\| {{z}_{1}} \right\|=\left\| {{z}_{2}} \right\|=.......\left\| {{z}_{n}} \right\|=1,\] then the value of \[\left\| {{z}_{1}}+{{z}_{2}}+....{{z}_{n}} \right\|-\left\| \frac{1}{{{z}_{1}}}+\frac{1}{{{z}_{2}}}+......+\frac{1}{{{z}_{n}}} \right\|\] is,
A.	0
B.	1
C.	\[-1\]
D.	None
Answer» B. 1

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If \[\left| {{z}_{1}} \right|=\left| {{z}_{2}} \right|=.......\left| {{z}_{n}} \right|=1,\] then the value of \[\left| {{z}_{1}}+{{z}_{2}}+....{{z}_{n}} \right|-\left| \frac{1}{{{z}_{1}}}+\frac{1}{{{z}_{2}}}+......+\frac{1}{{{z}_{n}}} \right|\] is,

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