If \[{{\left( \frac{x}{a} \right)}^{2}}+\left( {{\frac{y}{b}}^{2}} \right)=1(a>b)\] and \[{{x}^{2}}-{{y}^{2}}={{c}^{2}}\] cut at right angles, then

\[{{a}^{2}}-{{b}^{2}}={{c}^{2}}\]

\[{{a}^{2}}+{{b}^{2}}=2{{c}^{2}}\]

\[{{b}^{2}}-{{a}^{2}}=2{{c}^{2}}\]

\[{{a}^{2}}-{{b}^{2}}=2{{c}^{2}}\]

If \[{{\left( \frac{x}{a} \right)}^{2}}+\left( {{\frac{y}{b}}^{2}} \ri

1.	If \[{{\left( \frac{x}{a} \right)}^{2}}+\left( {{\frac{y}{b}}^{2}} \right)=1(a>b)\] and \[{{x}^{2}}-{{y}^{2}}={{c}^{2}}\] cut at right angles, then
A.	\[{{a}^{2}}+{{b}^{2}}=2{{c}^{2}}\]
B.	\[{{b}^{2}}-{{a}^{2}}=2{{c}^{2}}\]
C.	\[{{a}^{2}}-{{b}^{2}}=2{{c}^{2}}\]
D.	\[{{a}^{2}}-{{b}^{2}}={{c}^{2}}\]
Answer» D. \[{{a}^{2}}-{{b}^{2}}={{c}^{2}}\]

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If \[{{\left( \frac{x}{a} \right)}^{2}}+\left( {{\frac{y}{b}}^{2}} \right)=1(a>b)\] and \[{{x}^{2}}-{{y}^{2}}={{c}^{2}}\] cut at right angles, then

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