1.

If \(\left| {\begin{array}{*{20}{c}} {6i}&{ - 3i}&1\\ 4&{3i}&{ - 1}\\ {20}&3&i \end{array}} \right| = x + iy\), then the values of x and y are:

A. x = 0, y = 0
B. x = 0, y = 1
C. x = 0, y = -1
D. x = 1, y = -1
Answer» B. x = 0, y = 1


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