If \[\left| \,\begin{matrix} y+z & x & y \\ z+x & z & x \\ x+y & y & z \\ \end{matrix}\, \right|=k(x+y+z){{(x-z)}^{2}}\], then \[k=\]

\[{{x}^{2}}{{y}^{2}}{{z}^{2}}\]

If \[\left| \,\begin{matrix} y+z & x & y \\ z+x & z & x

1.	If \[\left\| \,\begin{matrix} y+z & x & y \\ z+x & z & x \\ x+y & y & z \\ \end{matrix}\, \right\|=k(x+y+z){{(x-z)}^{2}}\], then \[k=\]
A.	\[2xyz\]
B.	1
C.	\[xyz\]
D.	\[{{x}^{2}}{{y}^{2}}{{z}^{2}}\]
Answer» C. \[xyz\]

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If \[\left| \,\begin{matrix} y+z & x & y \\ z+x & z & x \\ x+y & y & z \\ \end{matrix}\, \right|=k(x+y+z){{(x-z)}^{2}}\], then \[k=\]

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