If \[\left| \,\begin{matrix} \cos (A+B) & -\sin (A+B) & \cos 2B \\ \sin A & \cos A & \sin B \\ -\cos A & \sin A & \cos B \\ \end{matrix}\, \right|=0\], then B = [EAMCET 2003]

If \[\left| \,\begin{matrix} \cos (A+B) & -\sin (A+B) & \cos 2B

1.	If \[\left\| \,\begin{matrix} \cos (A+B) & -\sin (A+B) & \cos 2B \\ \sin A & \cos A & \sin B \\ -\cos A & \sin A & \cos B \\ \end{matrix}\, \right\|=0\], then B = [EAMCET 2003]
A.	\[(2n+1)\frac{\pi }{2}\]
B.	\[n\pi \]
C.	\[(2n+1)\frac{\pi }{2}\]
D.	\[2n\pi \]
Answer» B. \[n\pi \]

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If \[\left| \,\begin{matrix} \cos (A+B) & -\sin (A+B) & \cos 2B \\ \sin A & \cos A & \sin B \\ -\cos A & \sin A & \cos B \\ \end{matrix}\, \right|=0\], then B = [EAMCET 2003]

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