If \[\left| \begin{matrix} a & \cot A/2 & \lambda \\ b & \cot B/2 & \mu \\ c & \operatorname{cotC}/2 & \gamma \\ \end{matrix} \right|=0,\] where a, b, c, A, B, and C are elements of a triangle ABC with usual meaning. Then, the value of a \[(\mu -\gamma )+b(\gamma -\lambda )+c(\lambda -\mu )=0\] is

If \[\left| \begin{matrix} a & \cot A/2 & \lambda \\ b &

1.	If \[\left\| \begin{matrix} a & \cot A/2 & \lambda \\ b & \cot B/2 & \mu \\ c & \operatorname{cotC}/2 & \gamma \\ \end{matrix} \right\|=0,\] where a, b, c, A, B, and C are elements of a triangle ABC with usual meaning. Then, the value of a \[(\mu -\gamma )+b(\gamma -\lambda )+c(\lambda -\mu )=0\] is
A.	\[0\]
B.	\[abc\]
C.	\[ab+bc+ca\]
D.	\[2abc\]
Answer» B. \[abc\]

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If \[\left| \begin{matrix} a & \cot A/2 & \lambda \\ b & \cot B/2 & \mu \\ c & \operatorname{cotC}/2 & \gamma \\ \end{matrix} \right|=0,\] where a, b, c, A, B, and C are elements of a triangle ABC with usual meaning. Then, the value of a \[(\mu -\gamma )+b(\gamma -\lambda )+c(\lambda -\mu )=0\] is

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