If \[\int{x\log \left( 1+\frac{1}{x} \right)dx}\]\[=f(x)\log (x+1)+g(x){{x}^{2}}+Lx+C\], then

If \[\int{x\log \left( 1+\frac{1}{x} \right)dx}\]\[=f(x)\log (x+1)+g(x

1.	If \[\int{x\log \left( 1+\frac{1}{x} \right)dx}\]\[=f(x)\log (x+1)+g(x){{x}^{2}}+Lx+C\], then
A.	\[f(x)=\frac{1}{2}{{x}^{2}}\]
B.	\[g(x)=\log x\]
C.	\[L=1\]
D.	None of these
Answer» E.

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If \[\int{x\log \left( 1+\frac{1}{x} \right)dx}\]\[=f(x)\log (x+1)+g(x){{x}^{2}}+Lx+C\], then

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