If\[\int{f(x)dx=g(x)+c}\], then \[\int{{{f}^{-1}}(x)dx}\] is equal to

1.	If\[\int{f(x)dx=g(x)+c}\], then \[\int{{{f}^{-1}}(x)dx}\] is equal to
A.	\[x{{f}^{-1}}(x)+C\]
B.	\[f({{g}^{-1}})(x))+C\]
C.	\[x{{f}^{-1}}(x)-g({{f}^{-1}})(x))+C\]
D.	\[{{g}^{-1}}(x)+C\]
Answer» D. \[{{g}^{-1}}(x)+C\]

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If\[\int{f(x)dx=g(x)+c}\], then \[\int{{{f}^{-1}}(x)dx}\] is equal to

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