If \[\int_{0}^{1}{{{\cot }^{-1}}(1-x+{{x}^{2}})dx=\lambda \int_{0}^{1}{{{\tan }^{-1}}xdx,}}\] then \[\lambda \] is equal to

If \[\int_{0}^{1}{{{\cot }^{-1}}(1-x+{{x}^{2}})dx=\lambda \int_{0}^{1}

1.	If \[\int_{0}^{1}{{{\cot }^{-1}}(1-x+{{x}^{2}})dx=\lambda \int_{0}^{1}{{{\tan }^{-1}}xdx,}}\] then \[\lambda \] is equal to
A.	1
B.	2
C.	3
D.	4
Answer» C. 3

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If \[\int_{0}^{1}{{{\cot }^{-1}}(1-x+{{x}^{2}})dx=\lambda \int_{0}^{1}{{{\tan }^{-1}}xdx,}}\] then \[\lambda \] is equal to

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