If in a triangle \[ABC\], \[\frac{\sin A}{4}=\frac{\sin B}{5}=\frac{\sin C}{6}\], then the value of \[\cos A+\cos B+\cos C\]is equal to

If in a triangle \[ABC\], \[\frac{\sin A}{4}=\frac{\sin B}{5}=\frac{\s

1.	If in a triangle \[ABC\], \[\frac{\sin A}{4}=\frac{\sin B}{5}=\frac{\sin C}{6}\], then the value of \[\cos A+\cos B+\cos C\]is equal to
A.	\[\frac{69}{48}\]
B.	\[\frac{96}{48}\]
C.	\[\frac{48}{69}\]
D.	None of these
Answer» B. \[\frac{96}{48}\]

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If in a triangle \[ABC\], \[\frac{\sin A}{4}=\frac{\sin B}{5}=\frac{\sin C}{6}\], then the value of \[\cos A+\cos B+\cos C\]is equal to

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