If \[{{I}_{n}}=\int{{{(\log x)}^{n}}\,\,dx},\] then \[{{I}_{n}}+n{{I}_{n-1}}=\] [Karnataka CET 2003]

If \[{{I}_{n}}=\int{{{(\log x)}^{n}}\,\,dx},\] then \[{{I}_{n}}+n{{I}_

1.	If \[{{I}_{n}}=\int{{{(\log x)}^{n}}\,\,dx},\] then \[{{I}_{n}}+n{{I}_{n-1}}=\] [Karnataka CET 2003]
A.	\[x{{(\log x)}^{n}}\]
B.	\[{{(x\log x)}^{n}}\]
C.	\[{{(\log x)}^{n-1}}\]
D.	\[n{{(\log x)}^{n}}\]
Answer» B. \[{{(x\log x)}^{n}}\]

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If \[{{I}_{n}}=\int{{{(\log x)}^{n}}\,\,dx},\] then \[{{I}_{n}}+n{{I}_{n-1}}=\] [Karnataka CET 2003]

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