If \[{{I}_{n}}=\int\limits_{0}^{\frac{\pi }{4}}{{{\tan }^{n}}x\,dx}\] then what is \[{{I}_{n}}+{{I}_{n-2}}\] equal to?

If \[{{I}_{n}}=\int\limits_{0}^{\frac{\pi }{4}}{{{\tan }^{n}}x\,dx}\]

1.	If \[{{I}_{n}}=\int\limits_{0}^{\frac{\pi }{4}}{{{\tan }^{n}}x\,dx}\] then what is \[{{I}_{n}}+{{I}_{n-2}}\] equal to?
A.	\[\frac{1}{n}\]
B.	\[\frac{1}{(n-1)}\]
C.	\[\frac{n}{(n-1)}\]
D.	\[\frac{1}{(n-2)}\]
Answer» C. \[\frac{n}{(n-1)}\]

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If \[{{I}_{n}}=\int\limits_{0}^{\frac{\pi }{4}}{{{\tan }^{n}}x\,dx}\] then what is \[{{I}_{n}}+{{I}_{n-2}}\] equal to?

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