MCQOPTIONS
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| 1. |
If h(n) is causal and h(n)=he(n)+ho(n),then what is the expression for h(n) in terms of only he(n)? |
| A. | h(n)=2h<sub>e</sub>(n)u(n)+h<sub>e</sub>(0)δ(n) ,n ≥ 0 |
| B. | h(n)=2h<sub>e</sub>(n)u(n)+h<sub>e</sub>(0)δ(n) ,n ≥ 1 |
| C. | h(n)=2h<sub>e</sub>(n)u(n)-h<sub>e</sub>(0)δ(n) ,n ≥ 1 |
| D. | h(n)=2h<sub>e</sub>(n)u(n)-h<sub>e</sub>(0)δ(n) ,n ≥ 0 |
| Answer» E. | |