If \[g(x)={{x}^{2}}+x-2\] and \[\frac{1}{2}\] (gof) \[(x)=2{{x}^{2}}-5x+2,\] then \[f(x)\] is equal to

If \[g(x)={{x}^{2}}+x-2\] and \[\frac{1}{2}\] (gof) \[(x)=2{{x}^{2}}-5

1.	If \[g(x)={{x}^{2}}+x-2\] and \[\frac{1}{2}\] (gof) \[(x)=2{{x}^{2}}-5x+2,\] then \[f(x)\] is equal to
A.	\[2x-3\]
B.	\[2x+3\]
C.	\[2{{x}^{2}}+3x+1\]
D.	\[2{{x}^{2}}-3x-1\]
Answer» B. \[2x+3\]

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If \[g(x)={{x}^{2}}+x-2\] and \[\frac{1}{2}\] (gof) \[(x)=2{{x}^{2}}-5x+2,\] then \[f(x)\] is equal to

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