If \[G\] be the geometric mean of \[x\] and \[y\], then \[\frac{1}{{{G}^{2}}-{{x}^{2}}}+\frac{1}{{{G}^{2}}-{{y}^{2}}}=\]

If \[G\] be the geometric mean of \[x\] and \[y\], then \[\frac{1}{{{G

1.	If \[G\] be the geometric mean of \[x\] and \[y\], then \[\frac{1}{{{G}^{2}}-{{x}^{2}}}+\frac{1}{{{G}^{2}}-{{y}^{2}}}=\]
A.	\[{{G}^{2}}\]
B.	\[\frac{1}{{{G}^{2}}}\]
C.	\[\frac{2}{{{G}^{2}}}\]
D.	\[3{{G}^{2}}\]
Answer» C. \[\frac{2}{{{G}^{2}}}\]

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If \[G\] be the geometric mean of \[x\] and \[y\], then \[\frac{1}{{{G}^{2}}-{{x}^{2}}}+\frac{1}{{{G}^{2}}-{{y}^{2}}}=\]

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