If \(\frac{x}{{{x}^{2}}-1}=\frac{A}{x-1}+\frac{B}{x+1}\), then find A – McqOptions

MCQOPTIONS

1.	If \(\frac{x}{{{x}^{2}}-1}=\frac{A}{x-1}+\frac{B}{x+1}\), then find A and B.
A.	2, 2
B.	1/2, 1/2
C.	1/2, -1/2
D.	2, -2
Answer» C. 1/2, -1/2

Discussion

No Comment Found

Related MCQs

A man has Rs.480 in the denominations of one-rupee notes, five-rupee notes and ten-rupee notes. The number of notes of each denomination is equal. What is the total number of notes that he has ?
(469 + 174)2 - (469 - 174)2 = ? (469 x 174)
A sum of Rs. 1360 has been divided among A, B and C such that A gets of what B gets and B gets of what C gets. B's share is:
If 2b = a + c and y2 = xz, then what is xb - c yc - a za - b‑ equal to?
1 ÷ [1 + 1 ÷ { 1 + 1÷( 1 + 1 ÷ 2)}] = ?
How many millimetres make ten kilometres?
7 – {4 × 3 – (-10) × 8 ÷ (-4)} is equal to∶
\(\left( {\frac{{\sqrt {625} }}{{11}} \times \frac{{14}}{{\sqrt {25} }} \times \frac{{11}}{{\sqrt {196} }}} \right)\) is equal to
In the decimal expression of \(\frac{1}{7000}\) the digit in the 7000th decimal place is
\(\frac{48 - 12\times 3+9}{12-9\div 3}\) is equal to -