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1. |
If \(\frac{{61}}{{19}}{\rm{}} = {\rm{}}3{\rm{\;}} + {\rm{\;}}\frac{1}{{x\; + \;\frac{1}{{y\; + \;\frac{1}{z}}}}}\) where x, y and z are natural numbers, then what is z equal to? |
A. | 1 |
B. | 2 |
C. | 3 |
D. | 4 |
Answer» D. 4 | |