1.

If \(\frac{{61}}{{19}}{\rm{}} = {\rm{}}3{\rm{\;}} + {\rm{\;}}\frac{1}{{x\; + \;\frac{1}{{y\; + \;\frac{1}{z}}}}}\) where x, y and z are natural numbers, then what is z equal to?

A. 1
B. 2
C. 3
D. 4
Answer» D. 4


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