If \[\frac{\pi }{2}\le x\le \frac{3\pi }{2},\]then\[{{\sin }^{-1}}(\sin x)\]is equal to

If \[\frac{\pi }{2}\le x\le \frac{3\pi }{2},\]then\[{{\sin }^{-1}}(\si

1.	If \[\frac{\pi }{2}\le x\le \frac{3\pi }{2},\]then\[{{\sin }^{-1}}(\sin x)\]is equal to
A.	x
B.	\[-x\]
C.	\[\pi +x\]
D.	\[\pi -x\]
Answer» E.

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If \[\frac{\pi }{2}\le x\le \frac{3\pi }{2},\]then\[{{\sin }^{-1}}(\sin x)\]is equal to

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