MCQOPTIONS
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| 1. |
If \[\frac{{{e}^{x}}}{1-x}={{B}_{0}}+{{B}_{1}}x+{{B}_{2}}{{x}^{2}}+...+{{B}_{n}}{{x}^{n}}\] then \[{{B}_{n}}-{{B}_{n-1}}\] is |
| A. | \[\frac{1}{n!}-\frac{1}{(n-1)!}\] |
| B. | \[\frac{1}{n!}\] |
| C. | \[\frac{1}{(n-1)!}\] |
| D. | \[\frac{1}{n!}+\frac{1}{(n-1)!}\] |
| Answer» C. \[\frac{1}{(n-1)!}\] | |