1.

If \[\frac{{{e}^{x}}}{1-x}={{B}_{0}}+{{B}_{1}}x+{{B}_{2}}{{x}^{2}}+...+{{B}_{n}}{{x}^{n}}\] then \[{{B}_{n}}-{{B}_{n-1}}\] is

A. \[\frac{1}{n!}-\frac{1}{(n-1)!}\]
B. \[\frac{1}{n!}\]
C. \[\frac{1}{(n-1)!}\]
D. \[\frac{1}{n!}+\frac{1}{(n-1)!}\]
Answer» C. \[\frac{1}{(n-1)!}\]


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