If \[\frac{c+i}{c-i}=a+ib\], where \[a,b,c\]are real, then \[{{a}^{2}}+{{b}^{2}}=\] [MP PET 1996]

If \[\frac{c+i}{c-i}=a+ib\], where \[a,b,c\]are real, then \[{{a}^{2}}

1.	If \[\frac{c+i}{c-i}=a+ib\], where \[a,b,c\]are real, then \[{{a}^{2}}+{{b}^{2}}=\] [MP PET 1996]
A.	1
B.	\[-1\]
C.	\[{{c}^{2}}\]
D.	\[-{{c}^{2}}\]
Answer» B. \[-1\]

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If \[\frac{c+i}{c-i}=a+ib\], where \[a,b,c\]are real, then \[{{a}^{2}}+{{b}^{2}}=\] [MP PET 1996]

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