1.

If \(\frac{{3\left( {{x^2} + 1} \right) - 7x}}{{3x}} = 6,\) x ≠ 0, then the value of \(\sqrt x + \frac{1}{{\sqrt x }}\;is:\)

A. \(\sqrt {\frac{{11}}{3}}\)
B. \(\sqrt {\frac{{25}}{3}}\)
C. \(\sqrt {\frac{{31}}{3}}\)
D. \(\sqrt {\frac{{35}}{3}}\)
Answer» D. \(\sqrt {\frac{{35}}{3}}\)


Discussion

No Comment Found