If \[\frac{1}{x}+x=2\cos \theta ,\] then \[{{x}^{n}}+\frac{1}{{{x}^{n}}}\] is equal to [UPSEAT 2001]

If \[\frac{1}{x}+x=2\cos \theta ,\] then \[{{x}^{n}}+\frac{1}{{{x}^{n}

1.	If \[\frac{1}{x}+x=2\cos \theta ,\] then \[{{x}^{n}}+\frac{1}{{{x}^{n}}}\] is equal to [UPSEAT 2001]
A.	\[2\cos n\theta \]
B.	\[2\sin n\theta \]
C.	\[\cos n\,\theta \]
D.	\[\sin \,n\theta \]
Answer» B. \[2\sin n\theta \]