If \[\frac{1}{b-c},\ \frac{1}{c-a},\ \frac{1}{a-b}\]be consecutive terms of an A.P., then \[{{(b-c)}^{2}},\ {{(c-a)}^{2}},\ {{(a-b)}^{2}}\] will be in

If \[\frac{1}{b-c},\ \frac{1}{c-a},\ \frac{1}{a-b}\]be consecutive ter

1.	If \[\frac{1}{b-c},\ \frac{1}{c-a},\ \frac{1}{a-b}\]be consecutive terms of an A.P., then \[{{(b-c)}^{2}},\ {{(c-a)}^{2}},\ {{(a-b)}^{2}}\] will be in
A.	G.P.
B.	A.P.
C.	H.P.
D.	None of these
Answer» B. A.P.

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If \[\frac{1}{b-c},\ \frac{1}{c-a},\ \frac{1}{a-b}\]be consecutive terms of an A.P., then \[{{(b-c)}^{2}},\ {{(c-a)}^{2}},\ {{(a-b)}^{2}}\] will be in

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