If \[f(x)={{x}^{2}}-1\] and \[g(x)=3x+1\], then \[(gof)(x)=\]

1.	If \[f(x)={{x}^{2}}-1\] and \[g(x)=3x+1\], then \[(gof)(x)=\]
A.	\[{{x}^{2}}-1\]
B.	\[2{{x}^{2}}-1\]
C.	\[3{{x}^{2}}-2\]
D.	\[2{{x}^{2}}+2\]
Answer» D. \[2{{x}^{2}}+2\]

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If \[f(x)={{x}^{2}}-1\] and \[g(x)=3x+1\], then \[(gof)(x)=\]

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