If \[f(x)={{(x+1)}^{\cot \,x}}\] is continuous at\[x=0\], then what is f (0) equal to?

If \[f(x)={{(x+1)}^{\cot \,x}}\] is continuous at\[x=0\], then what is

1.	If \[f(x)={{(x+1)}^{\cot \,x}}\] is continuous at\[x=0\], then what is f (0) equal to?
A.	1
B.	e
C.	\[\frac{1}{e}\]
D.	\[{{e}^{2}}\]
Answer» C. \[\frac{1}{e}\]

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If \[f(x)={{(x+1)}^{\cot \,x}}\] is continuous at\[x=0\], then what is f (0) equal to?

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