If \[f(x)=\log \left[ \frac{1+x}{1-x} \right]\], then \[f\left[ \frac{2x}{1+{{x}^{2}}} \right]\] is equal to [MP PET 1999; RPET 1999; UPSEAT 2003]

If \[f(x)=\log \left[ \frac{1+x}{1-x} \right]\], then \[f\left[ \frac{

1.	If \[f(x)=\log \left[ \frac{1+x}{1-x} \right]\], then \[f\left[ \frac{2x}{1+{{x}^{2}}} \right]\] is equal to [MP PET 1999; RPET 1999; UPSEAT 2003]
A.	\[{{[f(x)]}^{2}}\]
B.	\[{{[f(x)]}^{3}}\]
C.	\[2f(x)\]
D.	\[3f(x)\]
Answer» D. \[3f(x)\]

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If \[f(x)=\log \left[ \frac{1+x}{1-x} \right]\], then \[f\left[ \frac{2x}{1+{{x}^{2}}} \right]\] is equal to [MP PET 1999; RPET 1999; UPSEAT 2003]

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