If \[f(x)=\log \frac{1+x}{1-x}\], then \[f(x)\] is [Kerala (Engg.) 2002]

\[f({{x}_{1}})f({{x}_{2}})=f({{x}_{1}}+{{x}_{2}})\]

\[\frac{f({{x}_{1}})}{f({{x}_{2}})}=f({{x}_{1}}-{{x}_{2}})\]

If \[f(x)=\log \frac{1+x}{1-x}\], then \[f(x)\] is [Kerala (Engg.) 200

1.	If \[f(x)=\log \frac{1+x}{1-x}\], then \[f(x)\] is [Kerala (Engg.) 2002]
A.	Even function
B.	\[f({{x}_{1}})f({{x}_{2}})=f({{x}_{1}}+{{x}_{2}})\]
C.	\[\frac{f({{x}_{1}})}{f({{x}_{2}})}=f({{x}_{1}}-{{x}_{2}})\]
D.	Odd function
Answer» E.

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If \[f(x)=\log \frac{1+x}{1-x}\], then \[f(x)\] is [Kerala (Engg.) 2002]

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