If\[f(x)=ln(x-\sqrt{1+{{x}^{2}}})\], then what is \[\int{f''(x)dx}\] equal to?

\[\frac{1}{(x-\sqrt{1+{{x}^{2}}})}+c\]

\[-\frac{1}{\sqrt{1+{{x}^{2}}}}+c\]

\[\text{ln}\,(x-\sqrt{1+{{x}^{2}}})+c\]

If\[f(x)=ln(x-\sqrt{1+{{x}^{2}}})\], then what is \[\int{f''(x)dx}\] e

1.	If\[f(x)=ln(x-\sqrt{1+{{x}^{2}}})\], then what is \[\int{f''(x)dx}\] equal to?
A.	\[\frac{1}{(x-\sqrt{1+{{x}^{2}}})}+c\]
B.	\[-\frac{1}{\sqrt{1+{{x}^{2}}}}+c\]
C.	\[-\sqrt{1+{{x}^{2}}}+c\]
D.	\[\text{ln}\,(x-\sqrt{1+{{x}^{2}}})+c\]
Answer» C. \[-\sqrt{1+{{x}^{2}}}+c\]

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If\[f(x)=ln(x-\sqrt{1+{{x}^{2}}})\], then what is \[\int{f''(x)dx}\] equal to?

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