If \[f(x)=\left| \begin{matrix} {{x}^{n-1}} & \cos x & \frac{1}{x+3} \\ 0 & \cos \frac{n\pi }{2} & \frac{{{(-1)}^{n}}n!}{{{3}^{n+1}}} \\ \alpha & {{\alpha }^{3}} & {{\alpha }^{5}} \\ \end{matrix} \right|\] then \[\frac{{{d}^{n}}}{d{{x}^{n}}}\,\,{{[f(x)]}_{x=0}}=\]

If \[f(x)=\left| \begin{matrix} {{x}^{n-1}} & \cos x & \frac{1}{x

1.	If \[f(x)=\left\| \begin{matrix} {{x}^{n-1}} & \cos x & \frac{1}{x+3} \\ 0 & \cos \frac{n\pi }{2} & \frac{{{(-1)}^{n}}n!}{{{3}^{n+1}}} \\ \alpha & {{\alpha }^{3}} & {{\alpha }^{5}} \\ \end{matrix} \right\|\] then \[\frac{{{d}^{n}}}{d{{x}^{n}}}\,\,{{[f(x)]}_{x=0}}=\]
A.	\[1\]
B.	\[-1\]
C.	\[0\]
D.	None of these
Answer» D. None of these

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If \[f(x)=\left| \begin{matrix} {{x}^{n-1}} & \cos x & \frac{1}{x+3} \\ 0 & \cos \frac{n\pi }{2} & \frac{{{(-1)}^{n}}n!}{{{3}^{n+1}}} \\ \alpha & {{\alpha }^{3}} & {{\alpha }^{5}} \\ \end{matrix} \right|\] then \[\frac{{{d}^{n}}}{d{{x}^{n}}}\,\,{{[f(x)]}_{x=0}}=\]

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