If \[f(x)=\left\{ \begin{matrix} \frac{1-\sin x}{\pi -2x}, & x\ne \frac{\pi }{2} \\ \,\,\,\,\,\,\,\,\,\,\,\,\,\lambda \,, & x=\frac{\pi }{2} \\ \end{matrix} \right.\], be continuous at \[x=\pi /2,\] then value of \[\lambda \] is [RPET 2002]

If \[f(x)=\left\{ \begin{matrix} \frac{1-\sin x}{\pi -2x}, & x\ne

1.	If \[f(x)=\left\{ \begin{matrix} \frac{1-\sin x}{\pi -2x}, & x\ne \frac{\pi }{2} \\ \,\,\,\,\,\,\,\,\,\,\,\,\,\lambda \,, & x=\frac{\pi }{2} \\ \end{matrix} \right.\], be continuous at \[x=\pi /2,\] then value of \[\lambda \] is [RPET 2002]
A.	?1
B.	1
C.	0
D.	2
Answer» D. 2

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If \[f(x)=\left\{ \begin{matrix} \frac{1-\sin x}{\pi -2x}, & x\ne \frac{\pi }{2} \\ \,\,\,\,\,\,\,\,\,\,\,\,\,\lambda \,, & x=\frac{\pi }{2} \\ \end{matrix} \right.\], be continuous at \[x=\pi /2,\] then value of \[\lambda \] is [RPET 2002]

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