If\[f(x)=\left\{ \begin{align} & x,\,\,\text{when}\,x\,\text{is}\,\text{rational} \\ & 0\text{,}\,\,\text{when }x\text{ is irrational} \\ \end{align} \right.\]; \[g(x)=\left\{ \begin{align} & 0,\,\,\,\,\text{when}\,x\,\text{is}\,\text{rational} \\ & x,\,\,\,\,\text{when}\,x\,\text{is irrational} \\ \end{align} \right.\] then \[(f-g)\] is [IIT Screening 2005]

If\[f(x)=\left\{ \begin{align} & x,\,\,\text{when}\,x\,\text{is}\,\

1.	If\[f(x)=\left\{ \begin{align} & x,\,\,\text{when}\,x\,\text{is}\,\text{rational} \\ & 0\text{,}\,\,\text{when }x\text{ is irrational} \\ \end{align} \right.\]; \[g(x)=\left\{ \begin{align} & 0,\,\,\,\,\text{when}\,x\,\text{is}\,\text{rational} \\ & x,\,\,\,\,\text{when}\,x\,\text{is irrational} \\ \end{align} \right.\] then \[(f-g)\] is [IIT Screening 2005]
A.	One-one onto
B.	One-one not onto
C.	Not one-one but onto
D.	Not one-one not onto
Answer» B. One-one not onto

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