If \[f(x)=\left\{ \begin{align} & {{x}^{2}}\sin \frac{1}{x},\ \ \ \text{when }x\ne 0 \\ & \,\,\,\,\,\,\,\,\,\,\,\,\,\,0,\,\,\,\,\text{when}\,x=0 \\ \end{align} \right.\], then

If \[f(x)=\left\{ \begin{align} & {{x}^{2}}\sin \frac{1}{x},\ \ \ \

1.	If \[f(x)=\left\{ \begin{align} & {{x}^{2}}\sin \frac{1}{x},\ \ \ \text{when }x\ne 0 \\ & \,\,\,\,\,\,\,\,\,\,\,\,\,\,0,\,\,\,\,\text{when}\,x=0 \\ \end{align} \right.\], then
A.	\[f(0+0)=1\]
B.	\[f(0-0)=1\]
C.	f is continuous at\[x=0\]
D.	None of these
Answer» D. None of these

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If \[f(x)=\left\{ \begin{align} & {{x}^{2}}\sin \frac{1}{x},\ \ \ \text{when }x\ne 0 \\ & \,\,\,\,\,\,\,\,\,\,\,\,\,\,0,\,\,\,\,\text{when}\,x=0 \\ \end{align} \right.\], then

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