If \[f(x)=\left\{ \begin{align} & \frac{x\log \cos x}{\log (1+{{x}^{2}})},x\ne 0 \\ & \,\,\,\,\,\,\,\,\,\,\,\,0\,\,\,\,\,\,\,\,\,,x=0 \\ \end{align} \right.\text{then}\,\,\text{f(x)is}\] is

Continuous but not differentiable at x = 0

Continuous as well as differentiable at x = 0

Differentiable but not continuous at x = 0

Neither continuous nor differentiable at x = 0

If \[f(x)=\left\{ \begin{align} & \frac{x\log \cos x}{\log (1+{{x}^

1.	If \[f(x)=\left\{ \begin{align} & \frac{x\log \cos x}{\log (1+{{x}^{2}})},x\ne 0 \\ & \,\,\,\,\,\,\,\,\,\,\,\,0\,\,\,\,\,\,\,\,\,,x=0 \\ \end{align} \right.\text{then}\,\,\text{f(x)is}\] is
A.	Continuous as well as differentiable at x = 0
B.	Continuous but not differentiable at x = 0
C.	Differentiable but not continuous at x = 0
D.	Neither continuous nor differentiable at x = 0
Answer» B. Continuous but not differentiable at x = 0

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If \[f(x)=\left\{ \begin{align} & \frac{x\log \cos x}{\log (1+{{x}^{2}})},x\ne 0 \\ & \,\,\,\,\,\,\,\,\,\,\,\,0\,\,\,\,\,\,\,\,\,,x=0 \\ \end{align} \right.\text{then}\,\,\text{f(x)is}\] is

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