If \[f(x)=\left\{ \begin{align} & \frac{{{x}^{2}}-4x+3}{{{x}^{2}}-1},\ \text{for}\ x\ne 1 \\ & \ \ \ \ \ \ \ \ \ \ \ \ \ \ 2,\ \text{for }x=1 \\ \end{align} \right.\], then [IIT 1972]

\[\underset{x\to 1+}{\mathop{\lim }}\,f(x)=2\]

\[\underset{x\to 1-}{\mathop{\lim }}\,f(x)=3\]

\[f(x)\]is discontinuous at \[x=1\]

If \[f(x)=\left\{ \begin{align} & \frac{{{x}^{2}}-4x+3}{{{x}^{2}}-1

1.	If \[f(x)=\left\{ \begin{align} & \frac{{{x}^{2}}-4x+3}{{{x}^{2}}-1},\ \text{for}\ x\ne 1 \\ & \ \ \ \ \ \ \ \ \ \ \ \ \ \ 2,\ \text{for }x=1 \\ \end{align} \right.\], then [IIT 1972]
A.	\[\underset{x\to 1+}{\mathop{\lim }}\,f(x)=2\]
B.	\[\underset{x\to 1-}{\mathop{\lim }}\,f(x)=3\]
C.	\[f(x)\]is discontinuous at \[x=1\]
D.	None of these
Answer» D. None of these

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If \[f(x)=\left\{ \begin{align} & \frac{{{x}^{2}}-4x+3}{{{x}^{2}}-1},\ \text{for}\ x\ne 1 \\ & \ \ \ \ \ \ \ \ \ \ \ \ \ \ 2,\ \text{for }x=1 \\ \end{align} \right.\], then [IIT 1972]

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