If \[f(x)=\left\{ \begin{align} & 1+{{x}^{2}},\,\,\,\text{when}\,0\le x\le 1 \\ & 1-x\,\,\,,\text{when}\,\,x>1 \\ \end{align} \right.\], then

\[\underset{x\to {{1}^{+}}}{\mathop{\lim }}\,f(x)\ne 0\]

\[\underset{x\to {{1}^{-}}}{\mathop{\lim }}\,f(x)\ne 2\]

\[f(x)\]is discontinuous at \[x=1\]

If \[f(x)=\left\{ \begin{align} & 1+{{x}^{2}},\,\,\,\text{when}\,0\

1.	If \[f(x)=\left\{ \begin{align} & 1+{{x}^{2}},\,\,\,\text{when}\,0\le x\le 1 \\ & 1-x\,\,\,,\text{when}\,\,x>1 \\ \end{align} \right.\], then
A.	\[\underset{x\to {{1}^{+}}}{\mathop{\lim }}\,f(x)\ne 0\]
B.	\[\underset{x\to {{1}^{-}}}{\mathop{\lim }}\,f(x)\ne 2\]
C.	\[f(x)\]is discontinuous at \[x=1\]
D.	None of these
Answer» D. None of these

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If \[f(x)=\left\{ \begin{align} & 1+{{x}^{2}},\,\,\,\text{when}\,0\le x\le 1 \\ & 1-x\,\,\,,\text{when}\,\,x>1 \\ \end{align} \right.\], then

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