If \[f(x)=\frac{x}{x-1}\], then \[\frac{f(a)}{f(a+1)}=\] [MP PET 1996]

\[f\left( \frac{-a}{a-1} \right)\]

\[f\left( \frac{1}{a} \right)\]

If \[f(x)=\frac{x}{x-1}\], then \[\frac{f(a)}{f(a+1)}=\]

1.	If \[f(x)=\frac{x}{x-1}\], then \[\frac{f(a)}{f(a+1)}=\] [MP PET 1996]
A.	\[f(-a)\]
B.	\[f\left( \frac{1}{a} \right)\]
C.	\[f({{a}^{2}})\]
D.	\[f\left( \frac{-a}{a-1} \right)\]
Answer» D. \[f\left( \frac{-a}{a-1} \right)\]

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If \[f(x)=\frac{x}{x-1}\], then \[\frac{f(a)}{f(a+1)}=\] [MP PET 1996]

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