If \[f(x)=\frac{{{x}^{2}}-1}{{{x}^{2}}+1}\], for every real numbers. then the minimum value of f [Pb. CET 2001]

Does not exist because f is bounded

Is not attained even through f is bounded

If \[f(x)=\frac{{{x}^{2}}-1}{{{x}^{2}}+1}\], for every real numbers. t

1.	If \[f(x)=\frac{{{x}^{2}}-1}{{{x}^{2}}+1}\], for every real numbers. then the minimum value of f [Pb. CET 2001]
A.	Does not exist because f is bounded
B.	Is not attained even through f is bounded
C.	Is equal to +1
D.	Is equal to ?1
Answer» E.

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If \[f(x)=\frac{{{x}^{2}}-1}{{{x}^{2}}+1}\], for every real numbers. then the minimum value of f [Pb. CET 2001]

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