If \[f(x)=\frac{{{x}^{2}}-1}{{{x}^{2}}+1}\], for every real number x, then the minimum value of f [IIT 1998]

Does not exist because f is unbounded

Is not attained even though f is bounded

If \[f(x)=\frac{{{x}^{2}}-1}{{{x}^{2}}+1}\], for every real number x,

1.	If \[f(x)=\frac{{{x}^{2}}-1}{{{x}^{2}}+1}\], for every real number x, then the minimum value of f [IIT 1998]
A.	Does not exist because f is unbounded
B.	Is not attained even though f is bounded
C.	Is equal to 1
D.	Is equal to ?1
Answer» E.

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If \[f(x)=\frac{{{x}^{2}}-1}{{{x}^{2}}+1}\], for every real number x, then the minimum value of f [IIT 1998]

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