If \[f(x)=\frac{x}{1+x}\], then \[{{f}^{-1}}(x)\] is equal to [AMU 1999]

If \[f(x)=\frac{x}{1+x}\], then \[{{f}^{-1}}(x)\] is equal to [AMU 199

1.	If \[f(x)=\frac{x}{1+x}\], then \[{{f}^{-1}}(x)\] is equal to [AMU 1999]
A.	\[\frac{(1+x)}{x}\]
B.	\[\frac{1}{(1+x)}\]
C.	\[\frac{(1+x)}{(1-x)}\]
D.	\[\frac{x}{(1-x)}\]
Answer» E.

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If \[f(x)=\frac{x}{1+x}\], then \[{{f}^{-1}}(x)\] is equal to [AMU 1999]

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