If \[f(x)=\frac{\alpha x}{x+1},x\ne -1\], for what value of \[\alpha \] is \[f(f(x))=x\] [Kerala (Engg.) 2005]

If \[f(x)=\frac{\alpha x}{x+1},x\ne -1\], for what value of \[\alpha \

1.	If \[f(x)=\frac{\alpha x}{x+1},x\ne -1\], for what value of \[\alpha \] is \[f(f(x))=x\] [Kerala (Engg.) 2005]
A.	\[\sqrt{2}\]
B.	\[-\sqrt{2}\]
C.	1
D.	2
E.	?1
Answer» F.

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If \[f(x)=\frac{\alpha x}{x+1},x\ne -1\], for what value of \[\alpha \] is \[f(f(x))=x\] [Kerala (Engg.) 2005]

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