If \[f(x)=\frac{1}{4{{x}^{2}}+2x+1}\], then its maximum value is [RPET 2002]

If \[f(x)=\frac{1}{4{{x}^{2}}+2x+1}\], then its maximum value is �

1.	If \[f(x)=\frac{1}{4{{x}^{2}}+2x+1}\], then its maximum value is [RPET 2002]
A.	4/3
B.	2/3
C.	1
D.	¾
Answer» B. 2/3

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If \[f(x)=\frac{1}{4{{x}^{2}}+2x+1}\], then its maximum value is [RPET 2002]

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