If \[f(x+ay,\ x-ay)=axy\], then \[f(x,\ y)\] is equal to [AMU 2001]

\[\frac{{{x}^{2}}-{{y}^{2}}}{{{a}^{2}}}\]

\[{{x}^{2}}-{{a}^{2}}{{y}^{2}}\]

\[\frac{{{x}^{2}}-{{y}^{2}}}{4}\]

If \[f(x+ay,\ x-ay)=axy\], then \[f(x,\ y)\] is equal to �

1.	If \[f(x+ay,\ x-ay)=axy\], then \[f(x,\ y)\] is equal to [AMU 2001]
A.	xy
B.	\[{{x}^{2}}-{{a}^{2}}{{y}^{2}}\]
C.	\[\frac{{{x}^{2}}-{{y}^{2}}}{4}\]
D.	\[\frac{{{x}^{2}}-{{y}^{2}}}{{{a}^{2}}}\]
Answer» D. \[\frac{{{x}^{2}}-{{y}^{2}}}{{{a}^{2}}}\]

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If \[f(x+ay,\ x-ay)=axy\], then \[f(x,\ y)\] is equal to [AMU 2001]

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